Add(1)(2)(3)…(n)() in Javascript | Sum(1,2)(3,4) | Currying | Javascript Interview | Walmart

Sum(1)(2)(3)

function add(a){
 return function(b){
  return function(c){
   return a+b+c
  }
 }
}

function add(a) {
  return function(b){
    if(b){
      return add(a+b)
    }
    return a
  }
}

function sum(a,b) {
  return function(c,d){
    return a+b+c+d
  }
}

function add(...args) {
  let a = args.reduce((a, b) => a + b, 0)
  return function(...args){
    let b = args.reduce((a, b) => a + b, 0)
    if(b){
      return add(a+b)
    }
    return a
  }
}

So this is complex, right? You won’t be asked this question during your initial years of Javascript Interview but you never know. So, what’s happening here is, we are using inbuilt rest operators to take infinite arguments and then calculating the sum of all arguments. Rest remains the same as case 2.

If you have followed this far, do check out How to flatten a nested array in JS | Recursion | Javascript Interview | 1

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